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-12x^2-260x+1000=0
a = -12; b = -260; c = +1000;
Δ = b2-4ac
Δ = -2602-4·(-12)·1000
Δ = 115600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{115600}=340$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-260)-340}{2*-12}=\frac{-80}{-24} =3+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-260)+340}{2*-12}=\frac{600}{-24} =-25 $
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